How the quadratic may be factored by grouping 5x^2 + 17x – 40 = 0?

`5x^2+17x-40 = 0 `

`A=5`
 `b=17`   `c=-40`

Multiply `axxc` and find factors of that
number that minus to b

`-40xx5=-200`    factors of -200
that minus to 17 are 25, -8    plug these numbers into the
problem

`5x^2+25x-8x–40` now factor by
grouping

`(5x^2+25x)(-8x–40)`

Find
the greatest number the numbers in the parenthesis have in common and factor them
out

`5x(x+5)
-8(x+5)`

(5x-8) (x+5)

and
the answers are  (5x-8) (x+5)