Given the system of
equations:
2x + 6y =
12..............(1)
y= 3x + 5
.............(2)
We need to find the solution to the
system.
We will use the substitution method to
solve.
We will substitute (2) into
(1)
==> 2x + 6( 3x+5) =
12
==> 2x + 18x + 30 =
12
==> 20x = 12-
30
==> 20x =
-18
==> x = -18/20 =
-9/10
Now we will substitute into (2) to find
y.
==> y= 3x +5 = 3*-9/10 + 5 = (-27 + 50)/10 =
23/10
Then the answer is : x= -9/10 and y=
23/10
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