First we will write the equation into the slope
for,.
==> y-y1 = m(x-x1) such that (x1,y1) is any
point passes through the line and m is the
slope.
==> Given that the line passes through the
origin, then the line passes through the point
(0,0)
==> y- 0 =
m(x-0)
==> y=
mx..........(1)
now let us determine the
slope.
We know that the line 2y-4x + 4 = 0 is parallel to
our line.
Let us rewrite into the slops
form.
==> 2y=
4x-4
==> y= 2x-2
Then
the slope m = 2.
==> Then the equation
of the line is written y= 2x OR it is written y-2x =
0
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