The equation 11^(2x+1)=13 has to be solved for
x.
11^(2x+1)=13
Take the
logarithm of both the sides
`log(11^(2x+1))= log
13`
Use the property of logarithm `log a^b = b*log
a`
`(2x +1)*log 11 = log
13`
Isolate x to one of the
sides
`2x + 1 = (log 13)/(log
11)`
`2x = (log 13)/(log 11) -
1`
`x = ((log 13)/(log 11) -
1)/2`
The solution of the given equation is x = `((log
13)/(log 11) - 1)/2`
No comments:
Post a Comment