Th sum of three consecutive multiples of 5 is 120. Find the three integers.

Let the first number be
X

Then the second number is x+
5

Then the third number is x+
10

Now we are given that the sum of the three terms is
120.

==> x + x+ 5 + x+ 10 =
120

==> 3x + 15 =
120

Now we will subtract 15
.

==> 3x = 105

Now we
will divide by 3.

==> x =
35

Then the numbers are: 35, 40 , and
45.