The value if Kw is 9.55*10^-14 at a certain temperature , calculate the pH of water.

We'll recal that Kw = 1*10^-14 mol^2*dm^-6 at 25 Celsius
degrees.

Kw is also called the ionic product of water and
it varies with temperature.

Kw =
[H+]*[OH-]

But [H+]=[OH-] => Kw =
[H+]^2

We'll replace the value of
Kw:

9.55*10^-14 = [H+]^2

We'll
take square root both sides:

[H+] = sqrt
9.55*10^-14

[H+] =
3.09*10^-7

pH = -lg
3.09*10^-7

pH = lg (1/3.09) - lg
10^-7

pH = 7 - 0.48

pH =
6.52

Since pH is smaller than 7, then an acid solution is
dissolved in water.

The requested value of
pH, if Kw = 9.55*10^-14, is pH = 6.52.