For the triangle ABC with vertices A(-2,-1) , B(2,0),
C(0,6), the mid point of the side BC is ((2 + 0)/2 , (6 + 0)/2) or (1 ,
3)
The distance of the median AD is the distance from the
point A(-2 , -1) to (1, 3)
This is equal to sqrt[(-2 - 1)^2
+ (-1 - 3)^2]
=> sqrt [ 9 +
16]
=> sqrt
25
=>
5
The length of the median AD is
5
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