What are the intercepts of y= x^2 -4x + 5 ?

The intercepts of y= x^2 -4x + 5 have to be
determined.

At the point where the curve meets the x-axis,
the value of the y-coordinate is 0.

The equation x^2 - 4x +
5 = 0 has to be solved to determine the x-intercepts.

But
the equation x^2 - 4x + 5 = 0 does not have any real roots as (-4)^2 - 4*1*5 = -4 which
is negative.

The curve does not intersect the
x-axis.

At the point where it meets the y-axis, the x
coordinate is 0. This gives y = 0 - 0 + 5 = 0

The y
intercept of the curve is 5.

src="/js/tinymce/js/tinymce/plugins/asciisvg/js/d.svg"
sscr="-2.5,7.5,-3,7,1,1,1,1,1,300,200,func,x^2 -4x +
5,null,0,0,,,black,1,none"/>