The equation could be solved in 2 ways, at
least.
(x + pi/3) = arctan[tan(pi/2-x)] +
kpi
But tan (arctan x) = x
(x
+ pi/3) = (pi/2-x) + kpi
We'll add x both
sides:
2x = pi/2 - pi/3 +
kpi
2x = pi/6 + kpi
x = pi/12
+ kpi
Since x has to belong to the opened
interval (0,pi), then x = pi/12.
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