Calculate the area of the triangle with the following points:(-4, -10), (1, -3), (-2, -5)

Given the vertices's of the triangle are: (-4, -10) (1,-3)
and (-2,-5)

We will find the lnegth of the sides using the
distance between two points formula.

==> D1 = sqrt(
-4-1)62 + (-10+3)^2 = sqrt( 25 + 49) = sqrt(74)=
8.6

==> D2 = sqrt( -4+2)^2 + (-10+5)^2 = sqrt( 4 +
25) = sqrt(29)= 5.39

==> D3 = sqrt( 1+2)^2 +
(-3+5)^2 = sqrt( 9 + 4) = sqrt13=3.61

Now we will find the
perimeter.

==> P = 8.6 + 5.39 + 3.61 =
 17.6

==> s = p/2 = 17.6/2 =
8.8

Now we will find the
area.

==> A = sqrt s( s-a)(s-b)
(s-c)

==> A = sqrt( 8.8 * 5.19 * 3.41 *
0.2)

==> A = sqrt( 31.15) =
5.6

Then the area of the triangle is 5.6
square units ( approx.)