Since it is a quadratic equtaion, we'll apply quadratic
formula to determine it's roots.
x1 = [-b + sqrt(b^2 -
4ac)]/2a
x1 = [2 + sqrt(4 -
4*2*5)]/4
x1 =
(2+sqrt-36)/4
But sqrt(-36) =
sqrt(-1)*36
sqrt -1 =
i
sqrt(-36) = 6i or sqrt(-36) =
-6i
x1 = (2+6i)/4
x1 = 1/2 +
3i/2
The other root is the conjugate of x1, x2 = 1/2 -
3i/2.
The complex roots of the equation are:
{1/2 - 3i/2; 1/2 + 3i/2}.
No comments:
Post a Comment