Find the x-intercept and y-intercept for f(x) f(x)=x^2-3x+1

To determine x intercept, we'll put y = f(x) =
0.

But f(x) = x^2-3x+1 => x^2-3x+1 =
0

We'll apply quadratic
formula:

x1 = [3+sqrt(9 -
4)]/2

x1 = (3+sqrt5)/2

x2 =
(3-sqrt5)/2

The x intercepts are: ((3+sqrt5)/2 , 0) and
((3-sqrt5)/2) , 0).

To determine y intercepts, we'll cancel
the x coordinate.

f(0) = 0^2 - 3*0 +
1

f(0) = 1

The y intercept is
(0 , 1).

The x intercepts are ((3+sqrt5)/2 ,
0) and ((3-sqrt5)/2) , 0) and the y intercept is (0 ,
1).