Since the expression of f(x+1) is a linear function (f(-1)
is a constant), then f(x) is a linear function.
We'll write
the standard form of a linear function:
f(x) = ax +
b
We'll calculate f(-1):
f(-1)
= -a + b
Now, we'll calculate f(x+1) = a*(x+1) +
b
f(x+1) = ax + a + b (1)
But
the property of f(x) is f(x+1) = 2x+3+2*f(-1). (2)
Equating
(1) and (2), yields:
ax + a + b = 2x + 3 +
2*f(-1)
Comparing, we'll
get:
a = 2
a + b = 3 + 2*(-a +
b)
We'll replace a by it's value and we'll remove the
brackets:
2 + b = 3 - 4 +
2b
We'll shift b to the right side and -1 to the
left:
2 + 1 = 2b - b
b =
3
The requested function f(x) is f(x) = 2x +
3 and f(-1) = 1.
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