Solve the equations: 2y-5x+3 = 0 and 3y+x -5 = 0

2y - 5x + 3 =
0..........(1)

3y + x - 5 = 0
.............(2)

We will solve the system using the
elimination method.

We will multiply equation (2) by
5.

==> 15y + 5x - 25 =
0

Now we will add to
(1).

==> 17y - 22 =
0

==> 17y=
22

==> y= 22/17

Now we
will substitute into (2) to fin x.

==> x = 5- 3y= 5-
3(22/17) = (85-66)/17 = 19/17

Then the
solution to the equations is the pair ( 19/17 ,
22/17).