Saturday, March 31, 2012

Demonstrate that the fraction is a constant [log(x^2) + log(x^3)]/[ln(x^2)+ln(x^3)].

We'll prove that simplifying the fraction, the result does
not depend on the variable x.


We notice that the numerator
is a sum of logarithms that have matching bases.


We'll
apply the product rule:


log a + log b = log
(a*b)


log (x^2) + log (x^3) =
log (x^2*x^3)


log (x^2*x^3)= log
[x^(2+3)]


log (x^2) + log (x^3)
=  log (x^5)


We'll use the power rule of
logarithms:


log (x^5)= 5*log (x)
(1)


We also notice that the denominator is a sum of
logarithms that have matching bases.


[ln (x^2) + ln
(x^3)] = ln (x^5)


[ln (x^2) +
ln (x^3)] = 5*ln x (2)


We'll
substitute both numerator and denominator by (1) and
(2):


5*log (x) /5*ln x


We'll
simplify:


log (x) /ln x


We'll
transform the base of the numerator, namely 5, into the base
4.


ln x  = log (x) * ln
10


We'll re-write the
fraction:


log (x) /ln x = log (x) / log (x) * ln
10


We'll simplify:


1/ln
10


Since the result is not depending on the
variable x, the given fraction is a constant.

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