Factor and find the roots of (x^2 -2x - 99 ) = 0

The roots of the equation (x^2 -2x - 99 ) = 0 have to be
determined by factorization of the polynomial x^2 - 2x -
99.

To factor a polynomial of the form ax^2 + bx + c, write
b as a sum of two terms t1 and t2 such that t1 + t2 = b and t1*t2 =
a*c

x^2 - 2x - 99 = 0

We can
write -2 as the sum of -11 and 9, notice that the product of -11 and 9 is
-99*1

x^2 - 11x + 9x - 99 =
0

x(x - 11) + 9(x - 11) = 0

(x
+ 9)(x - 11) = 0

x + 9 = 0, x =
-9

x - 11 = 0, x = 11

The
solution of the equation x^2 - 2x - 99 = 0 = 0 is x = -9 and x =
11