Saturday, October 6, 2012

What is the vector u if u*v=12, u*w=14, v=6i+3j, w=2i+j ?

We'll write the vector u
as:


u = x*i + y*j


We'll
apply the definition of dot product.


u*v = (xi +
yj)(6i+3j)


u*v = 6xi^2 + 3xij + 6yij +
3yj^2


since the product of vectors ij = 0 and i^2 = j^2 =
1


u*v = 6x + 3y


We'll
substitute the information given in enunciation and we'll obtain the following
system:


6x + 3y = 12


2x + y =
4


y = 4 - 2x (1)


w*v = (xi +
yj)(2i+j)


u*w = 2x + y


2x + y
= 14 => y = 14 - 2x (2)


We'll equate (2) and
(1):


14 - 2x =  4 - 2x


14 = 4
impossible


Since we've get an impossible
equality, the vector u does not exist in the given
conditions.

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