Find the points where the line y = 2x+3 meets the line 2y-x+3 = 0

Given the lines:

y=
2x+3................(1)

2y-x + 3 =
0............(2)

We need to find the points of
interception.

We will substitute (1) into
(2).

==> 2(2x+3) - x + 3 =
0

==> 4x + 6 -x + 3 =
0

==> 3x =
-9

==> x =
-3

==> y= 2x+3 = 2*-3+3 =
-3

Then, the point of interception is (-3,
-3).