Find the x and y intercept of the curve y=x/(2x-3)^2.

y= x/(2x-3)^2

We need to find
the intercepts.

First we will find the y-intercept. Then
the value of x is zero.

==> y= 0/(2*0 3)^2 =
0

Then the y-intercept is the point
(0,0).

Now we will find the x-intercept. Then the value of
y is 0.

==> 0 =
x/(2x-3)^2

==> x =
0

Then the x-intercept is also
(0,0)

Then we have one intercept for both
axes which is the origin point: x = (0,0) and y =
(0,0).