We'll solve the equation considering 4 cases of
study.
The expressions 2x-3 and 2-3x can be either positive
or negative.
Case 1:
2x-3 =
2-3x
Case 2:
-(2x-3) =
2-3x
Case 3:
2x-3 =
-(2-3x)
Case 4:
-(2x-3) =
-(2-3x)
The Case 2 and Case 3 will have the same solution.
Also Case 1 and Case 4 will have the same solution. So, we'll solve just Case 1 and Case
2:
Case 1:
2x-3 =
2-3x
We'll isolate x to the left
side:
2x + 3x = 3+2
5x =
5
We'll divide by
5:
x =
1
Case
2:
-(2x-3) = 2-3x
We'll remove
the brackets:
-2x +3 =
2-3x
We'll isolate x to the left
side:
-2x + 3x =
2-3
x =
-1
The solutions of the
equation are: {-1 ; 1}.
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