Given the point (-3,7) passes through the
line.
Then we know that:
y-y1
= m(x-x1)
==> y-7 =
m(x+3)
Now we will determine the
slope.
Since the line is parallel to the line 2y-4x +2 = 0,
then the slopes are equal.
==> We will rewrite into
the slope form.
==> y= 2x
-1
==> Then the slope is m=
2
==> y-7=
2(x+3)
==> y-7 = 2x +
6
==> y= 2x +
13
Then the equation of the line is y=
2x+13.
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