Let's write the two steps of reaction of Na2CO3 with
HCl
Na2CO3 + HCl -> NaHCO3 +
NaCl
NaHCO3 + HCl -> H2O + CO2(g) +
NaCl
The volume of HCl used to titrate each 25mL of Na2CO3
is of 50mL.
Therefore, if you want to titrate 25mL of
Na2CO3, you'll have to use a volume of HCl which is twice then the volume of
Na2CO3.
If you have an amount of 20.5 mL of
HCl, then the amount of Na2CO3 is of 20.5/2 = 10.25
mL.
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