We need to define a transformation between the false scale
indication and the real temperature on a correct Celsius
scale.
The real extent of the incorrect scale
is
`Delta(T) = 105 -(-5) =110 degree C`
The length of incorrect scale
is
`L =100-0 =100 units`
The
real temperature for 40 units on the incorrect scale
is
`T_1 = L_1*(Delta(T))/L = 40*110/100 =40*1.1 =44 Celsius
`
The real temperature for 80 units on the incorrect scale
is
`T_2 =L_2*(Delta(T))/L =80*110/100 =80*1.1 =88 Celsius`
Answer: The correct temperatures
corresponding to 40 and 80 are 44 and 88 degree
Celsius
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