We are asked to find the lateral area of a right prism
which has an equilateral triangle as a base. The base edge is 5, and the height of the
prism is 9.
We will use the formula lateral area =
1/2(perimeter)(slant height)
=> A =
1/2pl
First, we will need to find (l) which is the slant
height of the prism. To do so, we need to apply the
following:
=> The given height is perpendicular to
the base. This creates a right triangle. We can use the Pythagorean Theorem to solve
for slant height of the triangle.
=> The slant
height is the hypotenuse of the triangle.
=>
One-half of the edge of the triangular base will be a leg of the right triangle.
Therefore, 2.5 is one leg of the triangle.
=> We
will use the given height as the other leg.
We substitute
these values into the Pythagorean Theorem and solve for the
hypotenuse.
c^2 = a^2 +
b^2
c^2 = 9^2 + 2.5^2
c^2 =
87.25
c = 9.34
We now use the
formula for lateral area.
LA =
1/2pl
(p) is the perimeter of the triangular base = 3(5) or
15.
(l)= 9.34
LA =
.5(15)(9.34)
LA = 70.05 sq.
units
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