Find the derivative of y= (2x-3) / (x^2-1)

We need to find the derivative of y = (2x - 3)/(x^2 -
1)

y = (2x - 3)/(x^2 -
1)

=> y = (2x - 3)(x^2 -
1)^(-1)

y' = 2*(x^2 - 1)^(-1) - (2x)(2x - 3)*(x^2 -
1)^(-2)

=> [2*(x^2 - 1) - (2x)(2x - 3)]/(x^2 -
1)^2

=> [2x^2 - 2 - 4x^2 + 6x]/(x^2 -
1)^2

=> [-2x^2 + 6x - 2]/(x^2 -
1)^2

The required derivative is [-2x^2 + 6x -
2]/(x^2 - 1)^2