Let us assume you are dropping the ball from a height H.
At the instant the ball leaves your hand it has no velocity. But a force of
gravitational attraction is acting on the ball that makes it accelerate downwards at 9.8
m/s^2. This number may vary slightly depending of the altitude and the resistance due to
air, but for general purposes we can take the figure to be 9.8
m/s^2.
The velocity of ball t seconds after it has left
your hand is equal to 9.8*t m/s.
The distance the ball
travels in t seconds is equal to (1/2)*9.8*t^2 m
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