Find the area of the rectangle if the perimeter is 38 and the length is 3 more than the width.

Let the length be L and the width be
W.

Then we know that the perimeter is
:

2L + 2W = 38

We will divide
by 2.

==> L + W =
19............(1)

Given that the length is 3 more than the
width.

==> L = w+
3.............(2)

We will substitute (2) into
(1).

==> w+ 3 + w =
19

==> 2w + 3 =
19

==> 2w =
16

==> w = 8

==>
L = 8+ 3 = 11

Now we will calculate the
area.

==> A = L*w = 8*11 =
88

Then the area of the rectangle is 88
square units.