Find the number of the solutions of equation 99sin^2x-101=-sin^2x.

The equation given is 99sin^2x-101=-sin^2x. The number of
roots of the equation have to be determined.

99(sin x)^2 -
101 = -(sin x)^2

=> 100(sin x)^2 =
101

=> (sin x)^2 =
101/100

=> sin x = sqrt (101/
100)

As sqrt (101/100) is greater than 1, and sin x can
only take values in [ -1 , 1], there are no
solutions.

99(sin x)^2 - 101 = -(sin x)^2
does not have any solutions