What is the equilibrium expression for equation C6H12O6+ 6O2----->6H2O + 6CO2

The equilibrium expression for any chemical reaction can
be determined if the phase of each substance that constitutes the chemical equation is
known and the equation is balanced with the same number of atoms of each element on both
the sides.

The equilibrium expression can be in terms of
the concentration of each substance that makes up the equation or if there are gases
involved it can be terms of the partial pressure. The equilibrium equation does not
include substances that solids or pure liquids or
solvents.

For the equation given: C6H12O6+
6O2----->6H2O + 6CO2, C6H12O6 is being oxidized to give water and carbon
dioxide.

C6H12O6 (s) + 6O2(g) -----> 6H2O(l) +
6CO2(g)

Here C6H12O6 is a solid and the water in the
products is a liquid.

We can write the equilibrium
constant

Kc =
[H20]^6*[CO2]^6/[O2]^6, where [X] is the concentration of X in moles per
liter and it is raised to power equal to the number of molecules in the balanced
chemical equation.

Kp =
[H2O]^6*P(CO2)^6/P(O2)^6 where P(X) is the partial pressure of X and it
is raised to the power equal to the number of molecules in the balanced chemical
equation.