Given that sinx - cosx =
5/7
We need to know that value
sinx*cosx
Let us square both
sides.
==> (sinx - cosx)^2 =
(5/7)^2
==> sin^2 x - 2sinx*cosx + cos^2 x =
25/49
But we know that sin^2cx + cos^2 x =
1
==> -2sinx*cosx + 1 =
25/49
We will subtract 1 from both
sides.
==> -2sinx*cosx = 25/49 -
1
==> -2sinxcosx =
-24/49
Now we will divide by
-2
==> sinx*cosx = -24/49*-2 =
12/49
Then the value is sinx*cosx =
12/49
No comments:
Post a Comment