Saturday, March 21, 2015

Given y'=e^(arctan x)/(x^2+1), what is the function y?

To determine the primitive function, we'll have to
calculate the indefinite integral of y'.


We'll apply
substitution technique, replacing arctan x by t.


arctan x =
t


We'll differentiate both sides and we'll
get:


dx/(1 + x^2) = dt


We'll
re-write the integral in the new variable:


Int e^(arctan x)
dx/(1 + x^2) =Int e^t*dt


Int e^t*dt = e^t +
C


Int e^(arctan x) dx/(1 + x^2) = e^(arctan x) +
C


The primitive function is: y = e^(arctan x)
+ C

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