x(x-40)(3x+2)= 240 can you find the value of X and show me how to get it

The equation to be solved is x(x-40)(3x+2)=
240

x(x-40)(3x+2)=
240

=> (x^2 - 40x)(3x + 2) =
240

=> 3x^3 - 120x^2 + 2x^2 - 80x =
240

=> 3x^3 -198x^2 - 80x =
240

=> 3x^3 -198x^2 - 80x - 240 =
0

It is not possible to solve for x using this equation
except by using the formula for roots of a cubic equation which is given at the link
provided below.

As the process of working out the roots is
a very tedious one I have only provided the final
results.

The roots of the equation are:
66.41, -0.2098 + i*1.077 and -0.2098 - i*1.077