This equation is also called biquadratic
equation.
To solve this equation, we'll reduce it to a
quadratic equation by replacing z^2 = x.
We'll re-write the
equation in x:
x^2 - 12x + 11 =
0
We'll apply quadratic
formula:
x1 = [12+
sqrt(144-44)]/2
x1 =
(12+10)/2
x1 = 11
x2 =
(12-10)/2
x2 = 1
But, we'll
have to find z1,z2,z3,z4.
z^2 =
x1
z^2 = 11
z1 = sqrt 11 and
z2 = -sqrt 11
z^2 = x2
z^2 =
1
z3 = -1 and z4 =
1
The solutions of the biquadratic equation
are: {-sqrt11 ; -1 ; 1 ; sqrt11}.
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