Find real solutions for the quadratic function 2x^2 -5x -8 = 0

Given the quadratic equation 2x^2 -5x -8 =
0

We will use the quadratic formula to find the
roots.

==> x= (-b+-sqrt(b^2-4ac)/
2a

We will
substitute:

==> a = 2       b= -5      c=
-8

==> x1= ( 5+sqrt( 25-4*2*-8) /
2*2

           = (5+ sqrt(89) /
4

==> x2= (
5-sqrt(89)/4

Then the real solutions for the function
are:

x = { (5+sqrt89)/4  , (5-sqrt89)/4
}