Solve the simultaneous equations y=x^2-3x+1 and y=2x^2+x+4 .

The set of simultaneous equations to be solved
is:

y=x^2-3x+1
...(1)

y=2x^2+x+4
...(2)

Equate (1) and
(2)

=> x^2-3x+1 =
2x^2+x+4

=> x^2 + 4x + 3 =
0

=> x^2 + 3x + x + 3 =
0

=> x(x + 3) + 1(x + 3) =
0

=> (x + 1)(x + 3) =
0

We get x = -1 and x =
-3

Substitute in (1)

For x =
-1, y = 1 + 3 + 1 = 5

For x = -3, y = 2*9 - 3 + 4 = 18 + 1
= 19

The solution of the equations are (-1,
5) and (-3 , 19)