Let ABC be a triangle.
Exend
AC to X from C.
Draw a line CD frm C which is || to
AB.
Now AB || CD and BC is a
transvalal.
Therefore angle ABC = angle BCD being alternate
angle.
Therefore angle CAB = angle DCX being corresponding
angles.
Therefore angle CAB + angle ABC +angle ACB = Angle
ACB+Angle ABD+Angle DCX. The right side is the sum of angle on the straight line, which
is 180 degree.
This proves that the sum of
the angles of a triangle is 180 degrees.
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