Calculate the expression sin(arcsin1/2)+sin(arccos scuare root 3/2).

We'll recall the fact that sin (arcsin x) = x and sin
(arccos x) = sqrt(1 - x^2)

Comparing, we'll
get:

sin (arcsin(1/2))= 1/2
(1)

sin (arccos (sqrt3)/2) = sqrt[1 -
(3/2)^2]

sin (arccos (sqrt3)/2) = sqrt (1 -
3/4)

sin (arccos (sqrt3)/2) = sqrt
[(4-3)/4]

sin (arccos (sqrt3)/2) = sqrt
(1/4)

sin (arccos (sqrt3)/2) = 1/2
(2)

We'll add (1) + (2):

sin
(arcsin(1/2)) + sin (arccos (sqrt3)/2) = 1/2 + 1/2

sin
(arcsin(1/2)) + sin (arccos (sqrt3)/2) =
1

The value of the given expression is sin
(arcsin(1/2)) + sin (arccos (sqrt3)/2) = 1.