What is the equation of median of BC if A(2,2) and the equations of medians of AC and AB are 2x+y-2=0, x-y+2=0?

The median that is running from the vertex A is
intercepting the other two medians. The intercepting point is the centroid of the
triangle ABC.

To write the equation of the median, we need
at least two points. Since we know the coordinates of the vertex A, we'll determine the
coordinates of the centroid. For this reason, we'll solve the system of equations of the
medians that are running from B and C vertices.

2x + y = 2
(1)

x - y = -2 (2)

We'll solve
this system using eliminationmethod. We'll add (1)+(2):

3x
= 0 => x = 0

0 - y = -2 => y =
2

Now, we'll write the equation of the median that is
running from A and passes through the centroid whose coordinates are
G(0,2):

(xG- xA)/(x - xA) =
(yG-yA)/(y-yA)

(0-2)/(x-2) = (2-2)/(y -
2)

We'll cross multiply and we'll
get:

0*(x-2) =
-2*(y-2)

-2*(y-2) = 0

y - 2 =
0

y = 2

The
requested equation of the median that is running from vertex A is y =
2.