Find antiderivative of the function given by ln(x+1)/(x+1)?

We have to find the anti derivative of [ln(x + 1)]/(x +
1)

The derivative of ln(x + 1) = 1/(x +
1)

Let ln(x + 1) = y

dy/dx =
1/(x + 1)

dy = dx/(x + 1)

Int
[ [ln(x + 1)]/(x + 1) dx]

use ln(x+1) = y and substitute as
shown earlier

=> Int [ y
dy]

=> y^2 / 2 +
C

Substitute y = ln (x +
1)

=> [ln( x + 1)]^2 / 2 +
C

The anti derivative of [ln(x + 1)]/(x + 1)
= [ln( x + 1)]^2 / 2 + C