Let the sides of the base be x and the height be
h.
Then the volume is given
by
v= x^2 * h .
==>
10,000 = x^2 h.............(1)
We need to find the minimum
surface area of the box.
We know that SA = area of the base
+ area of the sides.
==> SA = x^2 +
4(xh)
==> SA = x^2 +
4xh
But we know that h=
10000/x^2
==> SA = x^2 +
4x(10000/x^2)
==> SA = x^2 +
40,000/x
==> SA = (x^3 +
40,000)/x
Now we need to find the first derivative in order
to find the minimum value of SA.
==> SA' = (3x^2)(x)
- (x^3+4,000) / x^2
==> SA' = ( 3x^3 - x^3 -
40,000)/x^2 = 0
==> 2x^3 =
40,000
==> x^3 =
20,000
==> x = 27.14 (
nearly)
==> h= 10,000/x^2 = 10,000/736.081 =
13.57
Then the dimensions for the base is x=
27.14 and the height is h= 13.57 to have the maximum surface
area.
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