Sunday, December 29, 2013

How do we find u if 3u^3 - u^2 - 6u+ 2= 0

Given the polynomial
equation:


3u^3 - u^2 -6u + 2 =
0


First we will factor the
equation.


We will factor u^2 from the first 2
terms.


==> u^2 ( 3u - 1) - 6u + 2 =
0


Now we will factor -2 from the last two
terms.


==> u^2 ( 3u-1) -2 (3u -1) =
0


Now we will factor
(3u-1)


==> (3u-1)( u^2 -2) =
0


Now we will determine the
roots.


==> 3u-1 = 0 ==> 3u =1 ==> u=
1/3


==> (u^2-2) = 0 ==> u^2 = 2 ==> u=
+-sqrt2


Then we have three
roots.


==> u= { 1/3, sqrt2 ,
-sqrt2}

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