How to determine the coordinates of the vertex of parabola, v(h,k), if y=x^2-6x+8.

We'll write the function
as:

f(x) = a(x-h)^2 + k, where the vertex has the
coordinates v(h,k)

We'll write the given
function:

f(x) = 1(x^2 - 6x) + 8

We'll
complete the square x^2 - 6x:

x^2 -2*(3)*x + (3)^2 = (x -
3)^2

So, we'll add and subtract the value
9:

f(x) = 1(x^2 - 6x + 9) - 9 +
8

f(x) = (x - 3)^2 - 1

We'll
compare the result with the standard form:

(x - 3)^2 - 1=
a(x-h)^2 + k

h = 3

k =
-1

The coordinates of the vertex of parabola
are:V (3 ; -1).