The derivative of y = (sin x)(cos x) can be found using
the product rule.
y' = [(sin x)(cos
x)]'
=> [sin x]'[cos x] + [sin x][cos
x]'
=> [cos x][cos x] - [sin x][sin
x]
=> (cos x)^2 - (sin
x)^2
Use the relation (cos x)^2 + (sin x)^2 = 1 or (sin
x)^2 = 1 - (cos x)^2
=> (cos x)^2 - 1 + (cos
x)^2
=> 2*(cos x)^2 -
1
The result given by your calculator of
2*(cos x)^2 - 1 is equivalent to the result that you have got of (cos x)^2 - (sin
x)^2.
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