What is the circumference of the base of a cylinder if given the volume is 48 and the height is 7 ( I need the answer in terms of pi ).

Given the volume of the cylinder is 48 and the height is
7.

We will use the volume of a cylinder formula to find the
radius of the base.

==> V = r^2 * pi *
h

==> 48 = r^2 * pi *
7

==> r^2 = 48/7pi
=

==> r= sqrt(48/7pi)=
4sqrt(3/7pi)

Now we will calculate the circumference of the
base.

==> C = 2* r * pi = 2*4sqrt(3/7pi) *
pi

==> C = 8 sqrt(3/7)*
sqrtpi

==> C = 8
sqrt(3pi/7)

Then the circumference of the
base is C= 8sqrt(3pi/7) units.