How to write the quadratic x^2-14x+50 to the vertex form?

We'll recall the vertex form of the equation of a
parabola:

f(x) = a(x-h)^2 +
k

"a" represents the leading coefficient: a =
1

(h,k) are the coordinate of the vertex of
parabola.

We'll create a perfect square within the given
quadratic:

f(x) = (x^2 - 14x + 49) +
1

f(x) = (x - 7)^2 + 1

The
coordinates of the vertex of the parabola are (7 ,
1).

The vertex form of the given quadratic
f(x) = x^2 - 14x + 50 is f(x) = (x - 7)^2 + 1.