Let the small circumference be C1 and the larger
circumference be C2.
Given that C2 = 3*C1
........(1)
Given the area of the larger circle is
486
==> A2 = 486
We
need to find the area of the smaller circle.
==> A2
= 486 = r2^2 * pi
==> r2^2 = 486/pi =
154.7
==> r2=
12.44
==> C2 = 2*pi*r =
78.15
But C2 = 3C1
==>
C1 = 78.15/3 = 26.05
==> C1 = 2*pi * r1 =
26.05
==> r1 = 26.05/2pi =
4.15
==> A1 = r^2 * pi = 4.15^2 * pi =
54
Then the area of the smaller circle is 54
in^2.
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