What is the smallest positive value of x for which y = sin(3x + pi/2) has a maximum value?

We have to find the smallest value of x for which y =
sin(3x + pi/2) has the maximum value.

The sine function can
have a maximum value of 1.

We know that y = sin (3x + pi/2)
= 1. The least value of x for which the sine function has a value of 1 is
pi/2.

This gives 3x + pi/2 =
pi/2

=> 3x =
0

=> x =
0

The function y = sin(3x + pi/2) has the
maximum value when x = 0