We have (3x+2iy)-(y-2ix)-2x=3-2i and we need to find x and
y.
(3x + 2iy) -(y - 2ix) - 2x = 3 -
2i
=> 3x + 2iy - y + 2ix - 2x = 3 -
2i
=> x - y + 2i(x + y) = 3 -
2i
equate the real and imaginary
coefficients
x - y = 3 and x + y =
-1
adding the two
2x =
2
=> x = 1
y =
-2
The solution is x = 1 and y =
-2
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