Determine the quadratic function y=x^2-mx+8 if f(3)=4.

Given f(x)= x^2 - mx + 8

We
need to find the value of m such that f(3) = 3

We will
substitute with x= 3

==> f(3)= 3^2 - 3*m + 8 =
4

==> 9 - 3m + 8 = 4

We
will combine like terms.

==> -3m = 4 -8
-9

==> -3m = -13

Now we
will divide by -3

==> m = -13/-3 =
13/3

Then the value of m is
13/3

Then the quadratic function is :

f(x)= x^2 - 13 x /3+ 
8