We'll divide by 6 entire
equation:
x^2 + 6x + 3 =
0
Now, we'll shift 3 to the right to become much more easy
to see what has to be added to complete the square:
x^2 +
6x = -3
We'll consider the
formula:
(a+b)^2 = a^2 + 2ab +
b^2
We'll identify the first 2
terms:
a^2 = x^2 and 2*a*b =
2*x*3
The missing term is b and we'll identify it as being
3.
We'll raise to square 3 and we'll add it both
sides:
x^2 + 6x + 9 = -3 +
9
(x+3)^2 = 6
We'll take the
square root both sides:
x + 3 = sqrt
6
x = -3 + sqrt 6
x + 3 = -
sqrt 6
x = -3 - sqrt
6
The roots of quadratic have been determined
and they are:{-3 - sqrt 6 ; -3 + sqrt 6}.
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